On Tue, 08 Feb 2005 23:07:09 -0500, Caleb Hattingh <[EMAIL PROTECTED]> wrote: > '>>> a = [i*2*b for i in range(3) for b in range(4)] > '>>> a > [0, 0, 0, 0, 0, 2, 4, 6, 0, 4, 8, 12] > > Might take you a while to correlate the answer with the loop, but you > should be able to see after a while that this nesting is the same as > > '>>> a = [] > '>>> for b in range(4): > '>>> for i in range(3): > '>>> a.append(i*2*b)
There is a subtle error in this explanation. The equivilence actually looks like: '> a = [] '> l1 = range(4) '> l2 = range(3) '> for b in l1: '> for i in l2: '> a.append(i*2*b) Stephen -- http://mail.python.org/mailman/listinfo/python-list
