Neil Cerutti wrote: > For use in a hand-coded parser I wrote the following simple > iterator with look-ahead. I haven't thought too deeply about what > peek ought to return when the iterator is exhausted. Suggestions > are respectfully requested. As it is, you can't be sure what a > peek() => None signifies until the next iteration unless you > don't expect None in your sequence.
if you're doing simple parsing on an iterable, it's easier and more efficient to pass around the current token and the iterator's next method: http://online.effbot.org/2005_11_01_archive.htm#simple-parser-1 </F> -- http://mail.python.org/mailman/listinfo/python-list
