[EMAIL PROTECTED] a écrit : > Hi, > > The following code works - > > one = 1 > if one == 1: > ok = 1 > print ok > > but this does not, without exception - > > one = 2
Are you competing for the Most Misleading Name Award(tm) ?-) > if one == 1: > ok = 1 > print ok > > How do I establish before printing ok if it actually exists so as to > avoid this exception? The simplest way is to make sure the name will be defined whatever the value of the test: one = 42 # ... ok = (one == 1) print ok As a side note, if you want to check wether a name exists in the current namespace, you can use a try/except block: try: toto print "toto is defined" except NameError: print "toto is not defined" -- http://mail.python.org/mailman/listinfo/python-list
