First possible solution:
def rloop(seqin, comb):
# xcross product recipe 302478 by David Klaffenbach
if seqin:
for item in seqin[0]:
newcomb = comb + [item]
for item in rloop(seqin[1:], newcomb):
yield item
else:
yield comb
data = {1: [(3, 4), (5, 8)],
2: [(5, 4), (21, 3), (19, 2)],
3: [(16, 1), (0, 2), (1, 2), (3, 4)]}
print [sol for sol in rloop(data.values(), []) if 24==sum(el[0] for el
in sol)]
Bye,
bearophile
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