Dear all,
following are some piece of my code (mainly create a socket
connection to server and loop to receive data):
# function to create and return socket
def connect():
server_config = ('192.168.1.50', 3333);
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
sock.connect()
except socket.error:
print "Failed to connect"
return 0
return sock
# function to receive data
def recv_for_sock(sock):
sock.settimeout(25)
while 1:
if sock is None:
return 1
try:
recv_data = sock.recv(65535)
if recv_data:
.... # do something
except socket.timeout:
print "Socket Timeout"
time.sleep (10)
pass
except socket.error:
print "Socket Error"
time.sleep (10)
pass
# main function
if __name__ == '__main__':
sock = connect()
if sock:
errorno = recv_for_sock(sock)
... # other stuffs
else:
print "Cannot create connection"
...
my question is, when the socket (create a main function) is
disconnected by server (netstat status show close_wait), in
"recv_for_sock" function, it can catch the timeout exception at first
time. After then, the program will looping/hang within the
"recv_for_sock" function (actually is the socket.recv function) and
causing CPU usage to 99%. So, how to detect the socket connection is
closed at this case? I tried to use exception/check socket is None but
no help.
Thank for helping.
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