On Tue, 26 Dec 2006 16:50:06 -0700, gonzlobo wrote:
> I've been using Python for a few days. It's such the perfect language
> for parsing data!
>
> I really like it so far, but I'm having a hard time reading a file,
> reading the first few hex characters & converting them to an integer.
> Once the characters are converted to an integer, I'd like to write the
> data to another file.
>
> Here's the code snipped to the bare minimum:
> ---
> # Open File
> AP_File= open("AP.txt", "r")
> decoded_File= open("decoded.txt", "w")
>
> # read & process data line by line
> for line in AP_File:
> time = int(hex(line[0:8]), 16) * 0.0001 # this line is completely
> hosed!
> decodedFile.write(time)
What does "this line is completely hosed!" mean? Does it crash your PC?
Does it raise an exception? Do the wrong thing?
Try this:
for line in AP_File:
# Typical line looks like this:
# 000000d5 26 0600 80 00 ec 80 02 03 7d db 02 33
# This should convert to:
# 0.0213 26 0600 80 00 ec 80 02 03 7d db 02 33
time = int(line[0:8], 16) * 0.0001
line = str(time) + line[8:]
decodedFile.write(line)
You might need to think about how many decimal places you want the time to
store.
> My boss and I are trying to complete the same task (he figured out how
> to do it, but his code uses a while != "" loop and doesn't look
> pythony (it looks too 'c'). Not that there's anything wrong with that!
You can convert this:
AP_File= file("AP.txt", "r") # file is recommended over "open"
line = AP_File.readline()
while line != "":
do_something_with_line
line = AP_File.readline()
AP_File.close()
into this:
AP_File= file("AP.txt", "r")
for line in AP_File:
do_something_with_line
AP_File.close()
You need to look at what your boss does with the lines, not how he does
the loop.
--
Steven.
--
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