Steven D'Aprano wrote:
> Try something like this:
>
> # WARNING: untested
> def run_without_stdout(*args, **kwargs):
> function = args[0]
> args = args[1:]
> savestdout = sys.stdout
> sys.stdout = cStringIO.StringIO()
> result = None
> try:
> result = function(*args, **kwargs)
> finally:
> # don't forget to restore stdout, or you
> # really will regret it...
> sys.stdout = savestdout
> return result
>
Thanks!
I have tried your method, but I found it didn't work as expected.
The output produced by the external function couldn't be depressed,
but the "print " statement i wrote in python is depressed. It seems
make cStringIO.StringIO() as a temporary replacement of sys.stdout
has no effect on the external function.
Here is an example to make myself clear(actually it's modified version
of Steven's code):
def run_without_stdout(*args, **kwargs):
function = args[0]
args = args[1:]
savestdout = sys.stdout
sys.stdout = cStringIO.StringIO()
print "something"
result = None
try:
result = function(*args, **kwargs)
finally:
# don't forget to restore stdout, or you
# really will regret it...
sys.stdout = savestdout
print "some other thing"
return result
When run_without_stdout() is called, the "print" statements wrote in python
don't produce output, but function() produces output to the standard output
just as before:(
I have tried to replace sys.stdout globally with cStringIO.StringIO()
in my program(I mean, make "sys.stdout = cStringIO.StringIO()" as a
globall statement), but it worked just as previous version did.
Regards,
xiaojf
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