Pyenos wrote:
> Fredrik Lundh <[EMAIL PROTECTED]> writes:
>
>
>>Pyenos wrote:
>>
>>
>>>#############################CODE##############################
>>>t_len=0
>>>class WORK:
>>> def getwork(self):
>>> def formattable(table_to_process,type):
>>>TYPE=["p","t","T","s","i"] #list of types to format
>>> if type==TYPE[1]:
>>> def format_t():
>>> row=[]
>>> for col in table_to_process:
>>> #######################
>>> # ERROR PRONE PART #
>>> #######################
>>> if len(str(col))>t_len:
>>> t_len=len(str(col))
>>> #######################
>>># Error message says: #
>>># UnboundLocalError: local variable 't_len' referenced before assignment#
>>> row+=col
>>> if (table_to_process.index(col)+1)%7==0:
>>> t_temp.append(row)
>>> row=[]
>>> format_t()
>>>#################################################################
>>
>>wow.
>>
>>
>>>Interpreter says that t_len is local variable although i have
>>>specified t_len=0 in line 1. Also, although i've stated t_len=0 in
>>>line 1, it says that t_len is referenced before assignment.
>>
>>each function introduces a new scope.
>>
>></f>
>
>
> does class WORK inherit t_len=0 from line1?
>
> does def getwork() inherit t_len=0 from line1?
>
> does def formattable(table_to_process,type) inherit t_len=0 from line1?
>
> does def format_t() inherit t_len=0 from line1?
>
> thanks.
>
Yes and no, depending.
The rule of thumb I use is that if you assign in a function, the name is
not taken from the enclosing scope. For example, compare:
# example 1
def doit():
t_len = 42
def nested():
print t_len
nested()
doit() # will print 42
# example 2
def doit():
t_len = 42
def nested():
if t_len > 0:
print t_len
else:
t_len = 1
nested()
doit() # will get "referenced before assignment" error
You could make use of your WORK class here, depending on whether t_len
makes sense as a member of the WORK class:
class WORK:
t_len = 0
def getwork(self):
def formattable(table_to_process,type):
# etc., etc.
WORK.t_len = len(str(col))
James
--
James Stroud
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095
http://www.jamesstroud.com/
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