Thanks, that's an improvment (your first way). But I still wish I could find an even shorter (or more elegent) way of doing it. (Well, I guess if I expect every wish I have to come true I should at least wish for something more valuable.)
Thanks again, Gal On Dec 13, 3:58 pm, "Fredrik Lundh" <[EMAIL PROTECTED]> wrote: > "Gal Diskin" wrote: > > I am writing a code that needs to iterate over 3 lists at the same > > time, i.e something like this: > > > for x1 in l1: > > for x2 in l2: > > for x3 in l3: > > print "do something with", x1, x2, x3 > > > What I need to do is go over all n-tuples where the first argument is > > from the first list, the second from the second list, and so on... > > > I was wondering if one could write this more easily in some manner > > using only 1 for loop. > > What I mean is something like this: > > > for (x1,x2,x3) in (l1,l2,l3): > > print "do something with", x1, x2, x3how about > > for x1, x2, x3 in func(l1, l2, l3): > print x1, x2, x3 > > where func is defined as, say, > > def func(l1, l2, l3): > return ((x1, x2, x3) for x1 in l1 for x2 in l2 for x3 in l3) > > or if you prefer > > def helper(l1, l2, l3): > for x1 in l1: > for x2 in l2: > for x3 in l3: > yield x1, x2, x3 > > </F> -- http://mail.python.org/mailman/listinfo/python-list
