Laszlo Nagy wrote:
Sorry, I found it:
date = date-text / DQUOTE date-text DQUOTE
date-day = 1*2DIGIT ; Day of month
date-day-fixed = (SP DIGIT) / 2DIGIT ; Fixed-format version of date-day
date-month = "Jan" / "Feb" / "Mar" / "Apr" / "May" / "Jun" /
"Jul" / "Aug" / "Sep" / "Oct" / "Nov" / "Dec"
date-text = date-day "-" date-month "-" date-year
Is there a standard way to convert a datetime to this special, format or
should I write my own function?
If anyone is interested.
Keywords: IMAP, RFC3501, date format, search
"""Custom date class that 'knows' the date format as specified in RFC3501
IMAP4rev1"""
import datetime
class IMAPDate(datetime.date):
MONTHNAMES =
['Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec']
def to_imapdate(self):
"""Format a date as described in RFC3501."""
return "%d-%s-%d" % (
self.day,
self.MONTHNAMES[self.month-1],
self.year
)
@classmethod
def from_imapdate(cls,s):
"""Convert an IMAP style date format to an IMAPDate object."""
if isinstance(s,basestring):
parts = s.split('-')
ok = False
if len(parts) == 3:
try:
day = int(parts[0])
month = cls.MONTHNAMES.index(parts[1])+1
year = int(parts[2])
except:
pass
return cls(year,month,day)
if not ok:
raise ValueError("Invalid IMAP date format.
Please check RFC3501.")
else:
raise TypeError
if __name__ == '__main__':
date = IMAPDate.today()
fmt = date.to_imapdate()
print fmt
print IMAPDate.from_imapdate(fmt)
print IMAPDate.from_imapdate('32-Jan-2006')
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