I've been having trouble with a regular expression, and I finally simplified things down to the point that (a) my example is very simple, and (b) I'm totally confused. There are those who would say (b) is normal, but that's another thread.
I finally simplified my problem down to this simple case: re.match(r'\\this', r'\\this') Both the pattern and the string to match are identical raw strings, yet they don't match. What does match is this: re.match(r'\\\\this', r'\\this') Below are outputs from two versions of Python on two different machines, with identical outputs, so it's probably not a compiler problem or a version bug. What's going on here? Am I missing something obvious? linux25> python Python 2.2.3 (#1, Feb 2 2005, 12:22:48) [GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-49)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> print re.match(r'\\this', r'\\this') None >>> print re.match(r'\\\\this', r'\\this') <_sre.SRE_Match object at 0x6bf0e0> >>> C:\Dev\python>python ActivePython 2.4.2 Build 10 (ActiveState Corp.) based on Python 2.4.2 (#67, Jan 17 2006, 15:36:03) [MSC v.1310 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> print re.match(r'\\this', r'\\this') None >>> print re.match(r'\\\\this', r'\\this') <_sre.SRE_Match object at 0x009DA058> >>> -- Mike -- -- http://mail.python.org/mailman/listinfo/python-list
