On 12/1/06, Karl Kofnarson <[EMAIL PROTECTED]> wrote: [snip] > def fun_basket(f): > common_var = [0] > def f1(): > print common_var[0] > common_var[0]=1 > def f2(): > print common_var[0] > common_var[0]=2 > if f == 1: > return f1 > if f == 2: > return f2
Everytime you call fun_basket you create another common_var. > However, calling f1=fun_basket(1); f2 = fun_basket(2) and > then f1(); f2() returns 0 and 0. Two calls to fun_basket, two different common_var's, two f1's and two f2's. Each f1/f2 pair have access to a different common_var, so it's working as expected. To work as you expected, fun_basket should be on the same block common_var is defined. -- Felipe. -- http://mail.python.org/mailman/listinfo/python-list
