Thanks, John how about indexing 1-7, 10 [range(1:8),10] will generate [[1, 2, 3, 4, 5, 6, 7], 10], instead of [1, 2, 3, 4, 5, 6, 7, 10]
"John Machin 写道： " > hollowspook wrote: > > Hi, there > > > > a = range(100) > > > > if I want to use No 7, 11, 56,90 in a, then the only way I do is [a[7], > > a[11], a[56], a[90]]. > > Is there any other way? > > > > I presume a = range(100) is just an indication that a is a list -- the > literal answer to your question as asked is simply [7, 11, 56, 90] > > In the general case that a is *any* list (or anything else that > supports the index protocol, e.g. a string, a tuple, an array.array > instance, or some instance of a so-written class), you can use a "list > comprehension". Example: > > | >>> a = 'qwertyuiopasdfghjklzxcvbnm' > | >>> [a[x] for x in [25, 0, 13, 1]] > | ['m', 'q', 'f', 'w'] > > Do try and find "list comprehension" in the manual and in your book or > tutorial. It's useful for much more than the above. > > HTH, > John
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