As you no doubt have discovered from the docs and this group, that isn't doable with CPython.Dear list,
I have many dictionaries with the same set of keys and I would like to write a function to calculate something based on these values. For example, I have
a = {'x':1, 'y':2} b = {'x':3, 'y':3}
def fun(dict): dict['z'] = dict['x'] + dict['y']
fun(a) and fun(b) will set z in each dictionary as the sum of x and y.
My function and dictionaries are a lot more complicated than these so I would like to set dict as the default namespace of fun. Is this possible? The ideal code would be:
def fun(dict): # set dict as local namespace # locals() = dict? z = x + y
If you must write your functions as real functions, then you might do something like this:
>>> a = {'x':1, 'y':2}
>>> b = {'x':3, 'y':3}
...
>>> def funa(x,y, **kw):
... del kw #Careful of unwanted names in locals with this approach
... z = x + y
... return locals()
...
>>> a.update(funa(**a))
>>> b.update(funa(**b))
>>> a
{'y': 2, 'x': 1, 'z': 3}
>>> b
{'y': 3, 'x': 3, 'z': 6}
>>>
Alternatively, you could use exec:
>>> a = {'x':1, 'y':2}
>>> b = {'x':3, 'y':3}
>>> exec "z = x + y" in globals(), a
>>> a
{'y': 2, 'x': 1, 'z': 3}
>>> exec "z = x + y" in globals(), b
>>> b
{'y': 3, 'x': 3, 'z': 6}
>>>Michael
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