Jack,
I'm not using 2.4 yet; still back in 2.3x. :) Thanks for the examples, though - they are clear enough that I will probably use them when I upgrade.
Thanks, Alan
Jack Diederich wrote:
If you are using python2.4,
import itertools as it [x[0] for (x) in it.groupby([0,0,1,1,1,2,2,3,3,3,2,2,2,4,4,4,5])]
[0, 1, 2, 3, 2, 4, 5]
Since this is 2.4 you could also return a generator expression.
def iter_collapse(myList):
... return (x[0] for (x) in it.groupby([0,0,1,1,1,2,2,3,3,3,2,2,2,4,4,4,5]))
...
i = iter_collapse([0,0,1,1,1,2,2,3,3,3,2,2,2,4,4,4,5]) i
<generator object at 0xb7df6b2c>
list(i)
[0, 1, 2, 3, 2, 4, 5]
-Jack
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