Sam Loxton wrote:
> I am fairly new to the python language and am trying to sort a nested
> Dictionary of a Dictionary which I wish to sort by value. The dictionary
> does not have to be restructured as I only need it sorted in this way
> for printing purposes.
>
> The following is an example of my Dictionary printed with 'print
> dictionary.items()', where '2329513' is the key of the first hash, 'ops'
> is the key of the second hash and '50.0' is the value of the second hash
> which I would like to sort by:
> [('2329513', {'ops': 20.0}), ('2329492', {'ops': '80'}), ('2329490',
> {'ops': '50'})]
>
> I hope to sort these first keys by the value of the 'ops' key from
> highest to lowest value to give the following result:
> [('2329492', {'ops': '80'}), ('2329490', {'ops': '50'}), ('2329513',
> {'ops': 20.0})]
If Dennis' remarks don't apply because you simplified your problem for the
post:
>>> d = {'2329513': {'ops': 20.0}, '2329492': {'ops': '80'}, '2329490':
{'ops': '50'}}
>>> items = d.items()
>>> def key(item):
... return item[1]["ops"]
...
>>> items.sort(key=key, reverse=True)
>>> items
[('2329492', {'ops': '80'}), ('2329490', {'ops': '50'}), ('2329513', {'ops':
20.0})]
Peter
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