I was trying to find out what my value for filename is but it will not print. The file I am calling csoundgrid2.main seems to work fine when I call it directly from spe with two values and I have used this file dialog to load other files the error I am getting is. thanks for any help in advance
File "C:\Python24\Lib\site-packages\boa-constructor\test of snake\csoundgrid2.py", line 35, in loadFile infile = open(sys.argv[1], 'r') #The first argument passed in is the file name IndexError: list index out of range def sco_editor(self): "Pick a sco file and load it into a sco editor" dlg = wx.FileDialog(self,"load sco file", ".", "", "*.sco", wx.OPEN) try: if dlg.ShowModal() == wx.ID_OK: filename = dlg.GetPath() # Your code print filename csoundgrid2.main(filename, """;<sco_header>""") #("csoundgrid2.py", filename ,""";<sco_header>""", shell=True) #os.startfile('csoundgrid2.py', filename, """;<sco_header>""") finally: dlg.Destroy() https://sourceforge.net/project/showfiles.php?group_id=156455 http://www.dexrow.com -- http://mail.python.org/mailman/listinfo/python-list