David Isaac wrote: >>>> y > [116, 114, 121, 32, 116, 104, 105, 115] >>>> z=''.join(chr(yi) for yi in y) >>>> z > 'try this' > > What is an efficient way to do this if y is much longer? > (A numpy solution is fine.)
Here's another numpy solution just for fun:
import numpy
z = numpy.array(y,dtype='u1').view('S%d' % len(y))[0]
-Travis
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