"elake" (if that's supposed to be swedish, that should be "elak") wrote:
> I have a piece of code that I need some help with. It is supposed (in > my mind at least) take two arguments, a start path and a file > extension. Then when called it should return each of the file paths > that are found matching the criteria. It is only returning the first > file that it finds. What am I doing wrong? you can only return from a function once for each call. > # this is in a file called findFile.py > def findFileExt(startPath, fileExt): > for root, dirs, files in os.walk(startPath): > for file in files: > if file.endswith(fileExt): > filePath = str(os.path.join(root, file)) > return filePath and here you're doing exactly that. if you expect to be able to loop over the return value from findFileExt, replace that "return" with a "yield" (this turns the function into a generator). if you want to return a sequence, change the loop so it appends stuff to a list, and return that list when you're done. </F> -- http://mail.python.org/mailman/listinfo/python-list
