Thanks for the replies ... its perfect now ... but just one more thing ... how can I plot another function(a semi circle) in the same histogram?
thanks amit Robert Kern wrote: > [EMAIL PROTECTED] wrote: > > Thanks Robert, > > > > My previous problem is solved(I was using 'from matplotlib.pylab import > > *') but now I am facing another problem. I want to plot the histogram > > of eigenvalues calculated and I am using the following code: > > _______________________________________________________________________ > > import numpy > > from matplotlib import pylab > > > > n=100 > > ra = numpy.random > > la = numpy.linalg > > > > A = ra.standard_normal((n,n)) > > S = (A + numpy.transpose(A))/(2*n^(1/2)) > > Note that this line won't do what you think it does. First, one integer > divided > by another integer returns an integer, so (1/2) == 0. Also, ^ is not > exponentiation but bitwise XOR. Use ** for exponentiation. However, in this > case, you should use numpy.sqrt(). > > > eig = la.eigvals(S) > > > > [N,x]=pylab.hist(eig, 10) # make a histogram > > ------------------------------------------------------------------------------------------------------------- > > > > But again it is giving some error, which is given below: > > > > File "C:\Documents and Settings\amitsoni\Desktop\New > > Folder\wignerpython", line 15, in <module> > > [N,x]=pylab.hist(eig, 10) # make a histogram > > ValueError: too many values to unpack > > > > Can anyone help me out with this?? > > pylab.hist() does not return two values, it returns three. Sorry I didn't > catch > that earlier. > > -- > Robert Kern > > "I have come to believe that the whole world is an enigma, a harmless enigma > that is made terrible by our own mad attempt to interpret it as though it > had > an underlying truth." > -- Umberto Ec -- http://mail.python.org/mailman/listinfo/python-list
