K. Jansma wrote: > Hi, > > given an array: > > import numpy > a = numpy.arange(100).reshape((10,10)) > print a > > [[ 0 1 2 3 4 5 6 7 8 9] > [10 11 12 13 14 15 16 17 18 19] > [20 21 22 23 24 25 26 27 28 29] > [30 31 32 33 34 35 36 37 38 39] > [40 41 42 43 44 45 46 47 48 49] > [50 51 52 53 54 55 56 57 58 59] > [60 61 62 63 64 65 66 67 68 69] > [70 71 72 73 74 75 76 77 78 79] > [80 81 82 83 84 85 86 87 88 89] > [90 91 92 93 94 95 96 97 98 99]] > > > I'd like to create a new array that is a view of a, i.e. it shares data. If > a is updated, this new array should be automatically 'updated'. > > e.g. the array west should be a view of a that gives the element at the left > of location i,j in a. > a[i,j] = west[i,j+1] > > west can be created using: > > a[:,range(-1,a.shape[1]-1)] > > As you can see, this also defines periodic boundaries (i.e. west[0,0] = 9) > but it seems that this returns a copy of a, not a view. > How can I change the slice definition in such a way it returns a view?
You can't get periodic boundary conditions but a[:,1::] should give you (part of) the view you are looking for. -Travis -- http://mail.python.org/mailman/listinfo/python-list
