Fredrik Lundh schrieb: > [EMAIL PROTECTED] wrote: > > > Please consider that example: > > Python 2.4.3 (#69, Mar 29 2006, 17:35:34) [MSC v.1310 32 bit (Intel)] > > on win32 > > Type "help", "copyright", "credits" or "license" for more information. > >>>> s = 'foo' > >>>> f = lambda x: s > >>>> f(None) > > 'foo' > >>>> s = 'bar' > >>>> f(None) > > 'bar' > >>>> del(s) > >>>> f(None) > > Traceback (most recent call last): > > File "<stdin>", line 1, in ? > > File "<stdin>", line 1, in <lambda> > > NameError: global name 's' is not defined > > > > It seems to me, that f is referencing the name s instead of the string > > object bound to it > > that's how lexical scoping works, of course. > > if you want to bind to the object instead of the name, use explicit binding: > > f = lambda x, s=s: s > > </F>
Thank you, together with the response of Duncan it is clear to me now. I will use something like >>> def makefunc(t): ... return lambda x: t ... >>> s = 'foo' >>> f = makefunc(s) >>> f(None) 'foo' >>> s = 'bar' >>> f(None) 'foo' Leonhard -- http://mail.python.org/mailman/listinfo/python-list
