Fredrik Lundh wrote:
> it's slightly faster, but both your alternatives are about 10x slower
> than a straightforward:
> def balanced(txt):
> return txt.count("(") == txt.count(")")
I know, but if you read my post again you see that I have shown those
solutions to mark ")))(((" as bad expressions. Just counting the parens
isn't enough.
Bye,
bearophile
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