I ended up using len(sys.argv) > 1 for this particular problem. But I
think slicing is closer to the tool I was looking for.
I found a.has_key(k) or "k in a" for dictionaries - but haven't found
anything similar for lists. Does it exist?
I guess my example from php would technically be a dictionary in python
and not a list, it would nice to be able to quickly tell if a list key
existed or not.
Thanks!
Erik
Steve Holden wrote:
> [EMAIL PROTECTED] wrote:
> > Hi all,
> >
> > I'm sorry about the newbie question, but I've been searching all
> > afternoon and can't find the answer!
> >
> > I'm trying to get this bit of code to work without triggering the
> > IndexError.
> >
> > import shutil, os, sys
> >
> > if sys.argv[1] != None:
> > ver = sys.argv[1]
> > else:
> > ver = '2.14'
> >
> > Of course, whenever I run it, I get list index out of range.
> >
> > I'm coming from the php world where I can do:
> > if $_GET['var'] != Null {
> > $ver = $_GET['var'];
> > } else {
> > $ver = '2.14';
> > }
> >
> > Can anyone tell me how to make this work in python?
> >
> Well all the advice you've had so far seems good, but of course the
> simplest way is just to test the length of the sequence before you try
> to address its second element:
>
> if len(sys.argv) > 1:
> ver = sys.argv[1]
> else:
> ver = "2.14"
>
> regards
> Steve
> --
> Steve Holden +44 150 684 7255 +1 800 494 3119
> Holden Web LLC/Ltd http://www.holdenweb.com
> Skype: holdenweb http://holdenweb.blogspot.com
> Recent Ramblings http://del.icio.us/steve.holden
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