provowallis wrote:
> Hi all,
>
> I've been struggling with this for a while so I'm hoping that someone
> could point me in the right direction. Here's my problem: I'm trying to
> get the XPath for a given node in my document and then store that XPath
> as an attribute of the element itself. If anyone has a recommendation
> I'd be happy to hear it.
Sorry. I only check c.l.py once a week or so...
> For instance, I would take this XML
>
> ###before
>
> <?xml version="1.0"?>
> <hello-world>
> <greeter>An XSLT Programmer</greeter>
> <greeting>Hello, World!</greeting>
> </hello-world>
>
> ###after
>
> <?xml version="1.0"?>
> <hello-world>
> <greeter xp="hello-word[1]/greeter[1]">An XSLT Programmer</greeter>
> <greeting xp="hello-world[1]/greeting[1]">Hello, World!</greeting>
> </hello-world>
>
> ###
>
> import sets
> import amara
> from amara import binderytools
>
> doc = amara.parse('hello.xml')
> elems = {}
>
> for e in doc.xml_xpath('//*'):
>
> paths = elems.setdefault((e.namespaceURI, e.localName),
> sets.Set())
> path = u'/'.join([n.nodeName for n in
> e.xml_xpath(u'ancestor::*')])
> paths.add(u'/' + path)
>
> for name in elems:
>
> doc.name.km = elems[name]
It's a tougher problem than you may think :-)
Luckily it's a problem I've worked on. For discussion see:
http://www.xml.com/pub/a/2004/11/24/py-xml.html
For an updated solution see abs_path in Amara domtools. In most cases
you can safely call that on an Amara bindery node.
--
Uche Ogbuji Fourthought, Inc.
http://uche.ogbuji.net http://fourthought.com
http://copia.ogbuji.net http://4Suite.org
Articles: http://uche.ogbuji.net/tech/publications/
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