Hi. Presumably this is a easy question, but anyone who understands the sax
docs thinks completely differently than I do :-)
Following the usual cookbook examples, my app parses an open file as
follows::
parser = xml.sax.make_parser()
parser.setFeature(xml.sax.handler.feature_external_ges,1)
# Hopefully the content handler can figure out the encoding from the <?xml>
element.
handler = saxContentHandler(c,inputFileName,silent)
parser.setContentHandler(handler)
parser.parse(theFile)
Here 'theFile' is an open file. Usually this works just fine, but when the
filename contains u'\u8116' I get the following exception:
Traceback (most recent call last):
File "c:\prog\tigris-cvs\leo\src\leoFileCommands.py", line 2159, in
parse_leo_file
parser.parse(theFile)
File "c:\python25\lib\xml\sax\expatreader.py", line 107, in parse
xmlreader.IncrementalParser.parse(self, source)
File "c:\python25\lib\xml\sax\xmlreader.py", line 119, in parse
self.prepareParser(source)
File "c:\python25\lib\xml\sax\expatreader.py", line 111, in prepareParser
self._parser.SetBase(source.getSystemId())
UnicodeEncodeError: 'ascii' codec can't encode character u'\u8116' in
position 44: ordinal not in range(128)
Presumably the documentation at:
http://docs.python.org/lib/module-xml.sax.xmlreader.html
would be sufficient for a sax-head, but I have absolutely no idea of how to
create an InputSource that can handle non-ascii filenames.
Any help would be appreciated. Thanks!
Edward
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Edward K. Ream email: [EMAIL PROTECTED]
Leo: http://webpages.charter.net/edreamleo/front.html
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