Greetings,
I am working on a program to produce patterns. What would like is for
it to exhaustively produce all possible permutations of a sequence of
items but for each permutation produce variations, and also a sort of
stutter based on probability / weighted randomess.
Let us say we have tiles of four primary colors: ['Red', 'Blue',
'Green', 'Yellow']. Now we also have 4 alternatives or substitutes for
each color ['Maroon', 'Navy_Blue', 'Forest_Green', 'Dark_Brown']
We pick a unique permutation, say: ['Red', 'Blue', 'Yellow', 'Green']
Now I would like to pick the primary colors substitute (say 30% chance
for each element) so instead of our plain
['Red', 'Blue', 'Yellow', 'Green']
we might end up with:
['Red', 'Navy_Blue', 'Yellow', 'Forest_Green']
or
['Maroon', 'Navy_Blue', 'Yellow', 'Green']
Whatever... The main point is that sometimes the original color is
retained and sometimes the dark color is substituted.
Now I want to take this list and sometimes stutter an element so that
there is, let us say a 50% chance for each element, that it is
stuttered, and it may be repeated 1 (34%), 2(66%), or 3(33%) times. So
that we could get:
['Maroon','Maroon','Navy_Blue', 'Yellow','Yellow','Yellow','Yellow',
'Green']
The program would quit when all 24 (in the case of 4 elements) was
exhausted.
I have code that makes weighted randomness. I have code that makes
permutations, but I am having trouble putting this all together...
While i work on it though that i might ask for help... I'd like for the
code to be reusable and am building a library of functions for
patterns.
cheers,
kevin
### This is not mine, it is from a python book... I believe the Lutz
book
def permute(list):
if not list: # shuffle any
sequence
return [list] # empty
sequence
else:
res = []
for i in range(len(list)):
rest = list[:i] + list[i+1:] # delete
current node
for x in permute(rest): # permute the
others
res.append(list[i:i+1] + x) # add node at
front
return res
mport random
### This this is mine, but seems to work anyway hee hee
def windex(lst):
'''an attempt to make a random.choose() function that makes
weighted choices
accepts a list of tuples with the item and probability as a
pair
like: >>> x = [('one', 0.25), ('two', 0.25), ('three', 0.5)]
>>> y=windex(x)'''
n = random.uniform(0, 1)
for item, weight in lst:
if n < weight:
break
n = n - weight
return item
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