Simple list comprehension? >>> l = [1,2,3,4,5,6,7,8,9,0] >>> [(x, x+1) for x in l if x%2 == 1] [(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)]
Danny Neal Becker wrote: > George Sakkis wrote: > > > [EMAIL PROTECTED] wrote: > > > >> def transform(seq, size): > >> i = 0 > >> while i < len(seq): > >> yield tuple(seq[i:i+size]) > >> i += size > > > > Or for arbitrary iterables, not just sequences: > > > > from itertools import islice > > def transform(iterable, size): > > it = iter(iterable) > > while True: > > window = tuple(islice(it,size)) > > if not window: > > break > > yield window > > > > George > > > > Thanks guys! > > This one above is my personal favorite. -- http://mail.python.org/mailman/listinfo/python-list
