This is the error message that I'm having a tough time interpreting:
Traceback (most recent call last):
File "pagerank.py", line 101, in ?
main()
File "pagerank.py", line 96, in main
ch = strord(url)
File "pagerank.py", line 81, in strord
result[counter] = int(i);
ValueError: invalid literal for int(): i
and here is the full code:
def strord(url):
counter=0;
for i in url:
result[counter] = int(i);
counter += 1;
return result;
Thanks
Pontus Ekberg wrote:
> Melih Onvural wrote:
>
> > Group,
> >
> > I'm trying to get a very basic cast from a string to an integer
> > working. Here is what I'm doing:
> >
> > for i in url:
> > result[counter] = int(i)
> > counter += 1;
> >
> > return result;
> >
> > anything that I'm doing drastically wrong? Mac OS 10.4, MacPython
> > upgraded to 2.4. Thanks for any help,
> >
> > Melih
>
> In what way does it not work? Please post the entire code or at least the
> result of your code.
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