Tim Chase wrote: >> def remapmysql(a): >> return (a[0], (a[1:])) >> >> def test_map(): >> count = 100000 # count of simulated records >> l1 = range(0, count) >> l2 = range(count , 2 * count ) >> l3 = range(2 * count, 3 * count ) >> z1 = zip(l1, l2, l3) # simulate a mysql resultset >> >> d1 = dict(map(remapmysql,z1)) >> >> return d1 > > I'm not sure the map() is needed, as it could just be > > >>> d1 = dict((row[0], row[1:]) for row in z1) > > which worked in my tests. > > However either seems to work fairly well. > > -tkc >
thank you!! changed it, see previous post. -- http://mail.python.org/mailman/listinfo/python-list
