Dean Card wrote:
> I have a list of dictionaries where each dictionary defines, among other
> things, a row and column number. So, my list might look like this:
> [{'row':1, 'column':1, otherdata}, {'row':1, 'column':2, 'otherdata}...]
>
> This data is passed to flash and used there to create a grid of objects that
> are placed based on the row and column values.
>
> For a given set of data I may have values column values in the range of 1, 9
> inclusive.
>
> What I would like to do is take my list of dictionaries (like the one listed
> above) and shift the column numbers down to fill in missing values...
> example (only the column key,value pair is show for simplification):
>
> [{'column':1}, {'column':2}, {'column', 4}, {'column': 8}, {'column':2},
> {'column', 4}]
>
> If this were the dataset... I would want to change all 4s to 3 and all 8s to
> 4. That way I end up with 1 ... 4 instead of 1, 2, 4, and 8.
>
> Is there some slick way to do this?
Untested, but intended for Python 2.4:
list_o_dicts = [{'column': 1}, ...]
columns = set(x['column'] for x in list_o_dicts)
column_map = dict((column, i+1) for i, column in enumerate(sorted(columns)))
for d in list_o_dicts:
d['column'] = column_map[d['column']]
Of course, code that I wouldn't get fired for would have a slightly greater
line
count and fewer one-letter variable names.
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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