Tim Golden <[EMAIL PROTECTED]> wrote: > if os.path.isfile (filepath): > print filepath
You might get a more accurate result using os.access(filepath, os.X_OK) instead of os.path.isfile(filepath) Which checks the file is executable -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick -- http://mail.python.org/mailman/listinfo/python-list
