On Sat, 09 Sep 2006 09:00:35 -0700, John Machin wrote:
> jason wrote:
>> Hello,
>>
>> I am completely new to python and I have question that I unfortunately
>> could not find in the various documentation online. My best guess is
>> that the answer should be quitte easy but I have just enterd the
>> learning phase so that means a hightend chance for stupidity and
>> mistakes on my part.
>>
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...
</cut>
Owww.. Of course... ! Thankx for the answer and the suggestion. It really
helped me a lot. I defintely going to take the OO approach later on.
thankx again for the quick reply.
Jason.
> You are *assigning* records = blahblah each time around. "records" will
> end up being bound to the blahblah related to the *last* record that you
> read.
>
> You can do it item by item:
> records[folder]['date'] = datum
> etc
> or as a oneliner:
> records[folder] = {'date' : datum, 'mesgbytes' :
> extrmsize(str[8:]), 'mesgcount' : 1}
>
> When you find yourself using a dictionary with constant keys like
> 'date', it's time to start thinking OO.
>
> class LogMessage(object):
> def __init__(self, date, .....)
> self.date = date
> etc
>
> then later:
>
> records[folder] = LogMessage(
> date=datum,
> mesgbytes= extrmsize(str[8:]),
> mesgcount=1,
> )
>
>
> [snip]
>
> HTH,
> John
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