metaperl wrote: > On p.282 of "Python Cookbook" and in the Python docs on calling super: > http://www.python.org/download/releases/2.2.3/descrintro/#cooperation > > it is clear that the first argument to super is a class and not a type. > However, for the code below, I am getting an error when attempting to > provide a class as my first argument and don't understand why. Also, > since this is my first attempt at writing anything of any seriousness > in Python, any other feedback is welcome. > I believe it needs to be a class whose ultimate ancestor is "object", and not an "old-style" class. This is probably why the docs suggest a type is required.
regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://holdenweb.blogspot.com Recent Ramblings http://del.icio.us/steve.holden -- http://mail.python.org/mailman/listinfo/python-list
