Hello,
i'm looking for this behaviour and i write a piece of code which works,
but it looks odd to me. can someone help me to refactor it ?
i would like to walk across a list of items by series of N (N=3 below)
of these. i had explicit mark of end of a sequence (here it is '.')
which may be any length and is composed of words.
for: s = "this . is a . test to . check if it . works . well . it looks
. like ."
the output should be (if grouping by 3) like:
=> this .
=> this . is a .
=> this . is a . test to .
=> is a . test to . check if it .
=> test to . check if it . works .
=> check if it . works . well .
=> works . well . it looks .
=> well . it looks . like .
my piece of code :
import sys
class MyBuffer:
def __init__(self):
self.acc = []
self.sentries = [0, ]
def append(self, item):
self.acc.append(item)
def addSentry(self):
self.sentries.append(len(self.acc))
print >> sys.stderr, "\t", self.sentries
def checkSentry(self, size, keepFirst):
n = len(self.sentries) - 1
if keepFirst and n < size:
return self.acc
if n % size == 0:
result = self.acc
first = self.sentries[1]
self.acc = self.acc[first:]
self.sentries = [x - first for x in self.sentries]
self.sentries.pop(0)
return result
s = "this . is a . test to . check if it . works . well . it looks .
like ."
l = s.split()
print l
mb = MyBuffer()
n = 0
for x in l:
mb.append(x)
if x == '.':
# end of something
print "+", n
n += 1
mb.addSentry()
current = mb.checkSentry(3, True) # GROUPING BY 3
if current:
print "=>", current
--
http://mail.python.org/mailman/listinfo/python-list
