On 9/5/06, Tim Williams <[EMAIL PROTECTED]> wrote: > > It does already, you just haven't grasped list fully yet :):) > > > > when you remove 2 from alist, the list becomes length 2, there is no > > longer a 3rd item in the list to iterate over. > > > > Try this > > > > > >>> alist=[1 ,2 ,3, 4] > > > >>> for item in alist: > > > .... print item > > > .... if item==2: > > > .... alist.remove(item) > > > .... print alist > > > > sorry, I meant to offer an alternative also > > in yourgiven case you can iterate over a copy of the list like this: > > >>> for item in alist[:] : >
Thanks Tim. I suppose that does make sense. Iterating over a copy is a good alternative. -Greg -- http://mail.python.org/mailman/listinfo/python-list
