[EMAIL PROTECTED] wrote: > What is the correct way to download a file through HTTP and save it to > the file name suggested by "Content-Disposition"? >
Perhaps something along the lines of the following? >>> url = >>> r'http://www.4so9.com/cauca/files/ban-doc/francois/stingray/198%20lb%20stingray%201%20.JPG' >>> proxy = 'proxy02:8080' >>> import httplib >>> c = httplib.HTTPConnection(proxy) >>> c.request('GET', url) >>> resp = c.getresponse() >>> for k in resp.msg.keys(): ... print resp.msg.getallmatchingheaders(k) ... ['Content-Length: 64632\r\n'] ['Proxy-Connection: close\r\n'] ['X-Cache: HIT from SPSweb\r\n'] ['Accept-Ranges: bytes\r\n'] ['Server: Apache/2.0.51 (Fedora)\r\n'] ['Last-Modified: Fri, 03 Dec 2004 16:57:30 GMT\r\n'] ['ETag: "3b2375-fc78-8c13280"\r\n'] ['Date: Tue, 05 Sep 2006 10:35:48 GMT\r\n'] ['Content-Type: image/jpeg\r\n'] ['Age: 31440\r\n'] >>> data = resp.fp.read() >>> len(data) 64632 >>> data[:100] '\xff\xd8\xff\xe0\x00\x10JFIF\x00\x01\x02\x02\x00\x00\x00\x00\x00\x00\xff\xe1\x057Exif\x00\x00II*\x00\x08\x00\x00\x00\t\x00\x0f\x01\x02\x00\x06\x00\x00\x00z\x00\x00\x00\x10\x01\x02\x00\x13\x00\x00\x00\x80\x00\x00\x00\x12\x01\x03\x00\x01\x00\x00\x00\x01\x00\x00\x00\x1a\x01\x05\x00\x01\x00\x00\x00\x93\x00\x00\x00\x1b\x01\x05\x00\x01\x00\x00\x00\x9b\x00\x00\x00' >>> resp.fp.close() >>> -- http://mail.python.org/mailman/listinfo/python-list
