Dr. Pastor wrote: > In the following code I would like to ascertain > that x has/is a number. What the simplest TEST should be? > (Could not find good example yet.) > --- > x=raw_input('\nType a number from 1 to 20') > if TEST : > Do_A > else: > Do_B > --- > Thanks for any guidance. > > ----== Posted via Newsfeeds.Com - Unlimited-Unrestricted-Secure Usenet > News==---- > http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ > Newsgroups > ----= East and West-Coast Server Farms - Total Privacy via Encryption =----
To test if it *is* a number, the solution is pretty simple (s.isdigit() or an int(s) in a try..except ValueError), but if you want to test if it is or *has* a number, I think that the simplest solution would be a regexp: import re re_has_digit = re.compile(r'\d+') try: digits = re_has_digit.findall(input)[0] number = int(digits) print "%d is a number." % number except IndexError: print "'%s' has no number in it." % input I didn't try it, but it should work. -- http://mail.python.org/mailman/listinfo/python-list