>>>> foo = [-5,-1,2,3] # nearest value to zero ?
>>>> [value for value in foo if math.fabs(value) == min([int(math.fabs(x))
for x in foo])]
charles> [-1]
charles> Something simpler ?
Well, you can just use the abs() builtin instead of math.fabs. Also, just
compute the min/abs once:
minval = min([int(math.fabs(x)) for x in foo])
[value for value in foo if fabs(value) == minval]
Another way might be to sort by absolute value:
intermed = [(abs(v), v) for v in foo]
intermed.sort()
intermed[0][1]
That only gives you one of possibly many values closest to zero.
charles> How to extend this function to any given value ?
Just subtract that value from all values in the list:
intermed = [(abs(v-x), v) for v in foo]
intermed.sort()
intermed[0][1]
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