Is it possible to change the value of a variable in the outer function
if you are in a nested inner function?
For example:
def outer():
a = "outer"
def inner():
print a
a = "inner"
# I'm trying to change the outer 'a' here,
# but this statement causes Python to
# produce an UnboundLocalError.
return inner
What I'm trying to do here is to get the following output from these
lines of code?
# Code:
func = outer()
func()
func()
func()
# Output:
outer
inner
inner
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