On 2006-08-15, unexpected <[EMAIL PROTECTED]> wrote:
> If have a list from 1 to 100, what's the easiest, most elegant
> way to print them out, so that there are only n elements per
> line.
>
> So if n=5, the printed list would look like:
>
> 1 2 3 4 5
> 6 7 8 9 10
> 11 12 13 14 15
> etc.
>
> My search through the previous posts yields methods to print
> all the values of the list on a single line, but that's not
> what I want. I feel like there is an easy, pretty way to do
> this. I think it's possible to hack it up using while loops and
> some ugly slicing, but hopefully I'm missing something
I can't resist putting in my oar:
def print_per(seq, n, isep=" ", rsep="\n"):
"""Print the items in seq, splitting into records of length n.
Trailing records may be shorter than length n."""
t = len(seq)
for i in xrange(n, t+1, n):
print isep.join(map(str, seq[i-n:i]))+rsep,
t = t % n
if t > 0:
print isep.join(map(str, seq[-t:]))+rsep,
That's probably similar to some of the other mostly
non-functional solutions posted.
--
Neil Cerutti
--
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