Steve Holden wrote: > import xml.parsers.expat
Thanks, that worked. > > def r(): > return 1/0 > > try: > print r() > except: > import sys > t, v, tb = sys.exc_info() > > print "exception on line", tb.tb_lineno How do I get the helpful text that is thrown with the exception? Like if the exception is " IOError: [Errno 2] No such file or directory: 'out.xml' " How do I get the the text after IOError: ? Thanks again. -- http://mail.python.org/mailman/listinfo/python-list
