John Machin wrote: > alf wrote: > > Hi, > > > > I have a following task: let's say I do have an iterator returning the > > some objects: > > > > >>i=<iterator> > > >>i.next() > > 1 > > >>i.next() > > 'abgfdgdfg' > > >>i.next() > > <some object> > > > > > > For some reason I need to wrap thos objects with a list. I thought I > > could have a smart lamda or simple function class yielding following result: > > > > > > >>i=<iterator> > > >>i=list_wrapper(i) > > >>i.next() > > [1] > > >>i.next() > > ['abgfdgdfg'] > > >>i.next() > > [<some object>] > > > > > > What would thesolution? > > > > If I understand you correctly, something like this: > > >>> stuff = ['a', 'b', 'c', 'd'] > >>> i1 = iter(stuff) > >>> i1.next() > 'a' > >>> i1.next() > 'b' > >>> class LW(object): # ListWrapper > ... def __init__(self, i): > ... self.theiter = i > ... def next(self): > ... return [self.theiter.next()] > ... > >>> i2 = iter(stuff) > >>> x = LW(i2) > >>> x.next() > ['a'] > >>> x.next() > ['b'] > >>> x.next() > ['c'] > >>> x.next() > ['d'] > >>> x.next() > Traceback (most recent call last): > File "<stdin>", line 1, in ? > File "<stdin>", line 5, in next > StopIteration > > Cheers, > John
You could also use a generator comprehension: ([n] for n in i) |>> i = iter(xrange(3)) # iter() just for kicks.. |>> I = ([n] for n in i) |>> I.next() [0] |>> I.next() [1] |>> I.next() [2] |>> I.next() Traceback (most recent call last): File "<stdin>", line 1, in ? StopIteration Peace, ~Simon -- http://mail.python.org/mailman/listinfo/python-list
