Re: What's the cleanest way to compare 2 dictionary?

[Marc 'BlackJack' Rintsch]

In <[EMAIL PROTECTED]>, John Henry
wrote:

> When I do it under 2.3, I get:
> 
>     common_eq = set(k for k in _common if a[k] == b[k])
>                                    ^
> SyntaxError: invalid syntax
> 
> Don't know why that is.

There are no generator expressions in 2.3.  Turn it into a list
comprehension::
 
  common_eq = set([k for k in _common if a[k] == b[k]])

Ciao,
        Marc 'BlackJack' Rintsch
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