Peter Hansen <[EMAIL PROTECTED]> wrote: > snacktime wrote: > > I need to calculate the lrc of a string using an exclusive or on each > > byte in the string. How would I do this in python? > > lrc == Linear Redundancy Check? or Longitudinal? Note that > such terms are not precisely defined... generally just acronyms > people make up and stick in their user manuals for stuff. :-) > > import operator > lrc = reduce(operator.xor, [ord(c) for c in string])
Or for the full functional programming effect... lrc = reduce(operator.xor, map(ord, string)) which is slightly faster and shorter... $ python2.4 -m timeit -s'import operator; string = "abcdefghij13123kj12l3k1j23lk12j3l12kj3"' \ 'reduce(operator.xor, [ord(c) for c in string])' 10000 loops, best of 3: 20.3 usec per loop $ python2.4 -m timeit -s'import operator; string = "abcdefghij13123kj12l3k1j23lk12j3l12kj3"' \ 'reduce(operator.xor, map(ord, string))' 100000 loops, best of 3: 15.6 usec per loop -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick -- http://mail.python.org/mailman/listinfo/python-list
