Paul McGuire wrote: > I asked a very similar question a few weeks ago, and from the various > suggestions, I came up with this: > > expand = lambda lst,default,minlen : (lst + [default]*minlen)[0:minlen]
I wouldn't trust whoever suggested that. if you want a function, use a
function:
def expand(seq, default, minlen):
return (seq + [default]*minlen)[:minlen]
</F>
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