On 21 Jan 2005 08:31:02 -0800, Flavio codeco coelho <[EMAIL PROTECTED]> wrote: > hi, > > is there a faster way to build a circular iterator in python that by doing > this: > > c=['r','g','b','c','m','y','k'] > > for i in range(30): > print c[i%len(c)]
I don''t know if it's faster, but: >>> import itertools >>> c=['r','g','b','c','m','y','k'] >>> for i in itertools.islice(itertools.cycle(c), 30): ... print i -- Cheers, Simon B, [EMAIL PROTECTED], http://www.brunningonline.net/simon/blog/ -- http://mail.python.org/mailman/listinfo/python-list
