Hello,
*First question*
If the syntax of spawnl is:
spawnl(mode, path, ...)
Why does everyone write it like:
os.spawnlp(os.P_WAIT, 'cp', 'cp', 'index.html', '/dev/null')
or:
os.spawnl(os.P_WAIT, "/var/www/db/smm/smm_train", "smm_train",
"SMMTrainInput.xml")
How is the first 'cp' a path to a file? why does the desired executable have to
be named again as the first parameter?
*Second question*
I have a script test.py which calls another script sleep.py using a spawn.
--------------------------------------------------------------
#test.py
import os
os.spawnv(os.P_WAIT, "/var/www/db/cgi-bin/sleep.py", ["python", "sleep.py"])
#pid = os.spawnl(os.P_WAIT, 'sh', 'sh', '-cv', 'sleep 10; echo fark >
/tmp/test.out')
--------------------------------------------------------------
--------------------------------------------------------------
#sleep.py
import time
time.sleep(10)
--------------------------------------------------------------
I would expect that the test.py script should take 10sec to return. However it
returns immediatly. Perhaps I am calling the sleep.py script incorrectly?
Shouldn't it take 10sec to execute since the spawn mode argument is os.P_WAIT?
*Third question*
If I uncomment the second spawn call in test.py I do not get any output to
/tmp/test.out and it also returns immediatly. Can anyone tell me why?
Thank You Mighty Python Guru's,
Derek Basch
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