skull <[EMAIL PROTECTED]> writes:
Thank you for your replys.
lst[:] is did a solution, it makes a copy of list specially for iteration and
removes items from the original one.
but I still have an other thing to worry about coming with this way: does
performance sucks when the list is big enough?
It makes a copy operation!
here is a faster and 'ugly' solution:
lst = [1, 2, 3]
i = 0
while i < len(lst):
if lst[i] == 2:
lst.remove(i)
else:
i += 1
> Hi everybody, it is my first post in this newsgroup.
> I am a newbie for python though I have several years development experience
> in c++.
> recently, I was stumped when I tried to del item of a list when iteration.
>
> here is the wrong way I did:
>
> lst = [1, 2, 3]
> for i in lst:
> print i
> if i == 2:
> lst.remove(i)
>
> the result is:
>
> 1
> 2
>>>>
>
> as you would see, '3' is missing. this problem is caused by 'lst.remove(i)'.
> apparently, 'marked-and-sweep' is a solution to deal with this issue.
> but I think there SHOULD BE more 'wise' trick. I want to get your help.
>
> Thanks in advance.
>
> - skull
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