On Mon, 27 Dec 2004 18:49:14 +0100, François Granger <[EMAIL PROTECTED]> wrote: > Le 27/12/04 1:03, « Ishwor » <[EMAIL PROTECTED]> a écrit : > > > so indeed method 2 (l2.extend() ) is the fastest ?? In 2/3 times, > > method 3 (l3 += [x] seems faster than method 1/2 in my P2.4GHZ machine > > with 512mb??? :-( > > Could u run the code in your machine and perhaps and let me know what > > the average speed is?? > > On a iBook G4 à 1.2 Ghz loaded with tons of other softwares running. > > fgranger:/develop/python scripts fgranger$ python listspeed.py > @@@@@@@ > Method 1 done in (average finish time(out of 3)) - 5.6365475655 > Method 2 done in (average finish time(out of 3)) - 0.0562076569 > Method 3 done in (average finish time(out of 3)) - 0.0455052853 > @@@@@@@ > fgranger:/develop/python scripts fgranger$ python listspeed.py > @@@@@@@ > Method 1 done in (average finish time(out of 3)) - 6.1534483433 > Method 2 done in (average finish time(out of 3)) - 0.0637686253 > Method 3 done in (average finish time(out of 3)) - 0.0500767231 > @@@@@@@ > fgranger:/develop/python scripts fgranger$ python listspeed.py > @@@@@@@ > Method 1 done in (average finish time(out of 3)) - 5.5850391388 > Method 2 done in (average finish time(out of 3)) - 0.0594174862 > Method 3 done in (average finish time(out of 3)) - 0.0549054146 > @@@@@@@ > Thank you. ;-) method 3 ( l += [x] which maps to l.extend([x]) ) indeed seems fastest. well anyway i'll be using timeit module from now onwards as Steve pointed out. Thank you.
[snip] -- "On a cold day please heat your laptop using >>>while 1: pass " ;-) cheers, Ishwor Gurung -- http://mail.python.org/mailman/listinfo/python-list
